TS EAMCET 5-Aug-2021 Shift 2 Question Paper

Given,
Resistance of moving coil galvanometer, G=10Ω
Current, I=2mA=2×10−3A
Let R resistance is required to convert it to voltmeter,
Voltage rating be V1 to V2 i.e. 0 to 18V, respectively.
By using Ohm's law,
V‌‌=I(R+G)
R+G‌‌=V∕I
⇒‌‌R‌‌=‌

V

I

−G=‌

18×103

2

−10
‌‌=9000−10=8990Ω