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Question : 10 of 160
Marks:
+1 ,
-0
Solution:
f ( x ) = a x 2 − b x − a f ( x ) ≤ k f max = − [ ‌ ] = − ( ‌ ) when
a > 0 So, here
b 2 + 4 a 2 is a positive quantity
4 a is a negative quantity but,
− 4 a is a positive quantity
So,
f max is a positive quantity
And
f max = k Hence,
k > 0 .
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