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Question : 1 of 160
Marks:
+1,
-0
Solution:
f(x)=‌−tan(‌),−1<x<1 g(x)‌‌=√3+4x−4x2 ‌‌=√4−(2x−1)2 Domain of
f(x)⇒‌≠(2n+1)‌ x≠2n+1 Domain
⇒x∈(−1,1) Domain of
g(x)⇒4−(2x−1)2≥0 ⇒‌(2x−1)2≤4 ⇒‌−2≤2x−1≤2 ⇒‌−‌≤x≤‌ Domain of
g(x)⇒x∈[−‌,‌] Domain of
f(x)+g(x) will be
‌x∈(−1,1)∩x∈[−‌,‌] ⇒‌‌x∈[−‌,1)
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