TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Section: Mathematics

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Question : 71 of 160

Marks: +1, -0

The equation of the tangent to the curve xy5+2x2y−x3+y+1 = 0 at x=0 is

3x+4y+4 = 0
y = x−1
5x+7y+7 = 0
x+y+1 = 0

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