TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Section: Mathematics

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Question : 65 of 160

Marks: +1, -0

lim

x→−∞

‌‌‌

3|x|3−x2+2|x|−5

−5|x|3+3x2−2|x|+7

=

3
5
−5
7
5
7
−3
5

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