TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Section: Mathematics

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Question : 63 of 160

Marks: +1, -0

The Cartesian equation of a plane parallel to the plane

−

r

(2i+3j−4k)=1 and at a distance of 2 units from it is

2x+3y−4z = 3
2x+3y−4z = 1±2√29
2x+3y−4z = −1±2√29
2x+3y−4z = −3

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