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Question : 36 of 160
Marks:
+1,
-0
Solution:
P(1,2,3),Q(2,3,−4),R(3,−4,5) and
T=(x,y,z) ‌PQ=(1,1,−7) ‌QR=(1,−7,9) ‌PT=(x−1,y−2,z−3) PQ,QR and
PT are coplanar.
∴‌‌|| x−1 | y−2 | z−3 |
| 1 | 1 | −7 |
| 1 | −7 | 9 |
|=0 −40(x−1)−16(y−2)−8(z−3)=0 ⇒40x+16y+8z=96 ∴ Distance from origin
(0,0,0) ‌| |0+0+0−96| |
| √402+162+82 |
=‌=‌
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