For n,p∊\N-\{1\}, the coefficient of x^3 in {(1-x)^{-{1}/p}}/{(1-x)^n =

Correct Answer is : (np+1)(np+p+1)(np+2p+1)p3×3!

\frac{(np+1)(np+p+1)(np+2p+1)}{p^3\times3!}

{(np+1)(np+p)(np+2p)}/\begin{array}{cc}3! & p^3\end{array}

{(np+p)(np+2p)(np+3p)}/\begin{array}{cc}3! & p^3\end{array}

{(np+1)(np+2)(np+3)}/\begin{array}{cc}3! & p^3\end{array}

TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Section: Mathematics

Question : 18 of 160

Marks: +1, -0

For n,p∊N−{1}, the coefficient of x3 in

(1−x)−

(1−x)n

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