TS EAMCET 5-Aug-2021 Shift 1 Question Paper

[MnCl6]3−⇒ oxidation state of Mn is
x+6(−1)‌‌=−3
x‌‌=+3‌‌(Cl‌ is weak ligand ‌)
Mn‌‌=[Ar]3d54s2
Mn3+‌‌=[Ar]3d4 There are 4 unpaired electrons.
[Fe(CN)6]3−⇒ oxidation state of Fe is
‌x+6(−1)=−3⇒x=+3
Fe=[Ar]3d64s2
Fe3+=[Ar]3d5
CN is strong field ligand.1 unpaired electron in Fe3+.
[Co(C2O4)3]3−⇒ oxidation state of Co is
x+3(−2)‌‌=−3⇒x=+3
Co‌‌=[Ar]3d74s2
Co3+‌‌=[Ar]3d6
C2O4 is strong field ligand.Hence, 0 unpaired electron.
Ratio is 4: 1:0.