TS EAMCET 5-Aug-2021 Shift 1 Question Paper

4p orbital has one angular node and three maxima in its radial probability distribution curve As, number of angular node is equal to ' l '
l = azimuthal quantum number
l for s=0,l for p=1
l for d=2,l for f=3
So, angular node =1 (in 4p )
Number of radial nodes =n−l−1
For 4p, radial nodes =4−1−1=2
When radial nodes =2, maxima will be ' 3 '.
Thus ' 4p′ is correct answer.