TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Given, length of germanium rod, l=0.928cm
=0.928×10−2m
Area of cross-section, A=1mm2
Intrinsic charge carrier, ni=2.5×1019m−3,
Mobility of hole, µh=0.15m2V−1s−1
and mobility of electron, µe=0.35m2V−1s−1
As we know that,
Conductivity, σ=nie(µe+µh)
‌‌=2.5×1019×1.6×10−19(0.15+0.35)
‌‌=25×1.6×0.50
‌‌=4×0.5=2Ω−1m−1
Resistivity, ρ=‌

1

σ

=‌

1

2

=0.5Ω−m=50Ω−cm