The de-Broglie wavelength of an electron having kinetic energy 100 eV is [Use \h = 4.14\times10^{-15} \eVs, mass of electron = {\frac{0.5\times10^6}{c^2}} \eV, 1 \pm = 10^{-12}

TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Section: Physics

Question : 115 of 160

Marks: +1, -0

The de-Broglie wavelength of an electron having kinetic energy 100 eV is [Use h = 4.14×10−15 eVs, mass of electron =

0.5×106

eV, 1 pm = 10−12

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