TS EAMCET 4 May 2018 Shift 2 Solved Paper

The given points are A(1,0,0) and B(0,0,1)
The direction ratios of the points joining the lines are,
(x2−x1),(y2−y1), (z2−z1)
So, the equation of the plane for (-1,1,1) is,
(x−1)a+(y−0)b+(z−0)c=0
−(x−a)+z=0
π=−x+0y+z+a
=0
So,
x+y+z=6
The angle between the planes is given by,
cos‌θ=

(−1)(1)+0+(1)(1)

√1+0+1√1+1+1

cos‌θ=

−1+1

√2√3

=0
θ=

π

2