|\table 1, b c+a d , b^{2} c^{2}+a^{2} d^{2} ;1,c a+b d , c^{2} a^{2}+b^{2} d^{2} ;1,a b+c d , a^{2} b^{2}+c^{2} d^{2}|=

Correct Answer is : (a−b)(a−c)(b−c)(b−d) (a−d)(c−d)

(a-b)(b-c)(c-d)(a-d)(a-c) (d-b)

(a-b)(a-c)(b-c)(b-d) (a-d)(c-d)

(a-b)(a-c)(a-d)(b-c) (b-d)(d-c)

TS EAMCET 4 May 2018 Shift 2 Solved Paper

Section: Mathematics

Question : 5 of 160

Marks: +1, -0

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