TS EAMCET 4 May 2018 Shift 2 Solved Paper

Consider the equation,
x−2y−4=0
Now when rotate 30° clockwise,
So,
x=x′‌cos‌θ−y′‌sin‌θ
y=x′‌sin‌θ−y′‌cos‌θ
Then,
x=

x′√3

2

−

y′

2

and y=

x′

2

+

√3y′

2

So, the equation is,
[x=x′√32−

y′

2

]−2[

x′

2

+

√3y′

2

] −7=0
(

√3−2

2

)x′−(

1+2√3

2

)y′=7
So, the slope is given by,
m=

√3−2

1+2√3

=

1.732−2

1+2(1.732)

So, the integral part is (1).