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Question : 20 of 160
Marks:
+1,
-0
Solution:
The given equations are,
sin‌10°‌sin‌50°‌sin‌60°‌sin‌70°=m tan‌20°‌tan‌40°‌tan‌60°‌tan‌80°=n Then,
()[2‌sin‌10°‌sin‌50]‌sin‌70°=m [cos‌40°−cos‌60°]‌sin‌70°=m [cos‌20°−cos‌120°] −‌sin‌70°=m m= Now,
tan‌60°‌tan‌20°‌tan‌40°‌tan‌80°=n tan‌60°‌tan‌20°‌tan(60°−20°)‌tan(60°+20°)=n tan‌60°‌tan‌3(20°)=n n=3 This implies,
= =16√3
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