TS EAMCET 4 May 2018 Shift 2 Solved Paper

Consider the equation,
x3+3px2+3qx+r=0 ......(I)
Let the roots in HP be [2,3,6]
So,
x3−(2+3+6)x2+[2.3+2.6+3.6] x−2.3.6=0 ......(II)
x3−11x2+36x2−36=0
Compare equation (1) and (2).
3p=−11
p=−

11

3

And,
3q=36
q=12
And,
r=−36
Therefore, the correct option is (1).