TS EAMCET 4 May 2018 Shift 2 Solved Paper

The expression for Lorentz force on electron is given by,
F=q(E+v×B)
The value of force becomes 0 when a body performs a regular motion.
So,
E+(v×B)=0
E∥(v×B), also (v×B) is perpendicular to both v and B
Now,
E⊥v and E⊥B. Then,
E.v=0 and E.B=0
v.B=0
v⊥B
So, E⊥v⊥B
since,
E=v×B
E×B=(v×B)×B
v×B=vB

^

n

(vB)×B=v(B.B)
So,
v=

E×B

B.B

E=v×B
Now,
v×E=v×v×B=0≠B