TS EAMCET 4 May 2018 Shift 1 Solved Paper

Section: Mathematics

Question : 80 of 160

Marks: +1, -0

At any point on a curve, the slope of the tangent is equal to the stun of abscissa and the product of ordinate and abscissa of that point. If the curve passes through (0. 1). then the equation of the curve is

y = 2e
x2
2
- 1
y = 2ex2
y = e−x2
y = 2e−x2 - 1

Validate

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