TS EAMCET 4 May 2018 Shift 1 Solved Paper

Section: Mathematics

© examsiri.com

Question : 62 of 160

Marks: +1, -0

lim

x→−∞

3|x|−x

|x|−2x

-

lim

x→0

log(1+x3)

sin3x

=

1
1
3
4
3
0

Go to Question:

Prev Question

Next Question