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TS EAMCET 4 May 2018 Shift 1 Solved Paper
Show Para
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Section:
Mathematics
© examsiri.com
Question :
29 of 160
Marks:
+1
,
-0
Let
3
→
i
+
→
j
−
→
k
be the position vector of a point B. Let A be a point on the line which ispassing through B and parallel to the vector
2
→
i
−
→
j
+
2
→
k
. If
|
−
B
A
|
= 18 , then the position vector of A is
-
9
→
i
+
7
→
i
−
13
→
k
-
9
→
i
+
3
→
i
+
12
→
k
9
→
i
−
3
→
i
+
2
→
k
3
→
i
−
→
i
+
7
→
k
Validate
Solution:
BA is parallel to
2
^
i
−
^
j
+
2
^
k
So,
B
A
=
±
|
B
A
|
2
^
i
−
^
j
+
2
^
k
√
2
2
+
1
2
+
2
2
=
±
12
^
i
−
6
^
j
+
12
^
k
Therefore,
O
A
−
O
B
=
±
12
^
i
−
6
^
j
+
12
^
k
O
A
=
3
^
i
+
^
j
−
^
k
±
(
12
^
i
−
6
^
j
+
12
^
k
)
=
15
^
i
−
5
^
j
+
11
^
k
or
−
9
^
i
+
7
^
j
−
13
^
k
© examsiri.com
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