TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Given, initial pressure, pi=105Pa
Initial temperature, Ti=20∘C
Final temperature, Tf=127∘C
Coefficient of linear expansion, α=10−5C−1
Bulk modulus of metal, B=2×1011N∕m2
As we know that,
B=‌

−p

∆V∕V

where, ∆V∕V is volumetric strain.
⇒‌‌p=B‌

∆V

V

. . . (i)
and since ‌

∆V

V

=γ∆T put in Eq. (i), we get
where, γ= volumetric expansion.
∴‌‌‌‌=Bγ∆T
‌‌=B3α∆T
‌‌=2×1011×3×10−5(127−20)
‌‌=6×106(107)=642×106
‌‌=6.42×108N∕m2
‌∼eq6×108Pa