TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Given, m1 and m2 are two masses,
Initial speed of m2,u2=0 and height of m2 from ground =h. Let tension in rope be T and acceleration of block be a.
∴ From force equation of body of mass m2,
m2g−T=m2a . . . (i)
Force of equation of body of mass m1,
T=m1a . . . (ii)
From Eqs. (i) and (ii), we have
⇒‌m2g−m1a‌‌=m2a
⇒‌m2g‌‌=a(m1+m2)
⇒‌a=‌

m2g

m1+m2

By using third equation of motion,
v2−u2=2ah
where, v is final speed and u is initial speed.
∴‌v2−02‌=2ah
⇒‌v‌=√2ah
=√2×‌

m2g

m1+m2

×h
=√(‌

m2

m1+m2

)2gh