TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Given, time taken by the stone to cover distance d1,t1=4s
Time taken by the stone to cover distance d2, t2=8s
∵ Stone is falling freely, hence its initial speed u is zero and acceleration due to gravity, g=10m∕s2.
As we know that,
h‌‌=ut+(‌

1

2

)gt2
∴‌‌d1‌‌=0+(‌

1

2

)×10×42
‌‌=80m
Let distance travelled by stone in total time t=4s+8s=12s be d
Again from Eq. (i), we get
d‌‌=‌

1

2

×10×122
‌‌=5×144
‌‌=720m
∴‌‌d2‌‌=d−d1
d2‌‌=720−80
‌‌=640m
‌ Now, ‌‌‌‌

d2

d1

‌‌=‌

640

80

=8