TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Section: Mathematics

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Question : 77 of 160

Marks: +1, -0

For x>0

∫(

√1+x+x2

1+x

+

1

2√1+x+x2

−

1

(1+x)√1+x+x2

)‌d‌x =

1
√1+x+x2
+C
√1+x+C
1
√1+x
+C
√1+x+x2+C

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