TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Section: Mathematics

Question : 58 of 160

Marks: +1, -0

P is a point on the conic a2x2+b2y2 = a2(a2+b2−y2) and S is a focus of that conic. M is the foot of the perpendicular from P on to a directrix ofGiven conic, a2x2+b2y2=a2‌left(a2+b2−y2‌right) that conic nearer to S. If PM = KSP, then K =

b
√a2+b2
√a2+b2
b
a
√a2+b2
√a2+b2
a

Validate

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