TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Let slope of line AB be m, then equation of AB y−5=m(x−3) . . . (i)
Coordinate of A for y=0
x=3−‌

5

m

. . . (i)
A(3−‌

5

m

,0)
Coordinate of B for x=0
y=5−3m . . . (iii)
B(0,5−3m)
Eliminating m from Eqs. (ii) and (iii), we get
(x−3)(y−5)=15
⇒xy−5x−3y=0‌ or ‌5x−xy+3y=0
Comparing with ax+2hxy+by=0, we get
a=5,h=‌

−1

2

‌ and ‌b=3
Then, a+b+h=5+3−‌

1

2

=‌

15

2