TS EAMCET 4-Aug-2021 Shift 2 Question Paper

In 40 consecutive integers 20 are even and 20 are odd.
Number of ways of selecting two integers =‌40C2
Sum is odd, when one integer is even and other is odd.
Number of ways of selecting one even and one odd integer =‌20C1×‌20C1
∴ Required probability =‌

‌20C1×‌20C1

‌40C2

=‌

20×20

40×39 2×1

=‌

20

39