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Question : 26 of 160
Marks:
+1,
-0
Solution:
tanh−1(x)‌‌=‌‌log(‌) ‌ and ‌coth−1(x)‌‌=‌‌log(‌) ∴tanh−1(‌)‌+coth−1(2) ‌‌=‌‌log(‌)+‌‌log(‌) =‌‌‌[log(‌)+log(3)] =‌(log‌2+log‌3) =‌‌log‌6 =log‌√6
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