TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Given reaction is disproportionation reaction, same species is oxidised and reduced in the same reaction. Formation of sodium thiosulphate (Na2S2O3) is favoured when there is more NaOH in the solution.

1S8

Octasulphur

+

12NaOH

Sodium‌hydroxide

⟶

4Na2S

Sodium‌sulphide(P)

+

2Na2S2O3

Sodium‌thiosulphate(Q)

+

6H2O

Water

Here, a=1,b=12,q=2 and r=6.
Hence, product P is Na2S (sodium sulphide) and Q is Na2S2O3 (sodium thiosulphate).