TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Given, electric field, E=5×105V
Kinetic energy for conduction electron,
K=3.2×10−20J
Width of depletion region be d.
As we know that,
V=‌

W

q

and ‌‌V=E⋅d
Here, V= electric potential, W= work
and q= charge of electron, i.e. 1.6×10−19C.
∴‌‌E⋅d=‌

W

q

⇒‌‌d=‌

W

qE

=‌

K

qE

⇒‌‌d=‌

3.2×10−20

1.6×10−19×5×105

=‌

3.2

8

×10−20−5+19=0.4×10−6m
=4×10−5cm