TS EAMCET 4-Aug-2021 Shift 2 Question Paper

As we know that for photoelectric effect, the incident energy should be always greater than threshold energy.
and since KE=(l∕2)mv2=hv−hv0=h(v−v0)
where, KE= kinetic energy, h= Planck's constant, v= frequency and v0= threshold frequency.
Since, KE>0
v>v0