TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Given, initial, final pressure and temperature of surrounding pi,pf and Ti,Tf.
We know that, adiabatic relation between p and T is given as
p1−γTγ= constant
where, γ is adiabatic constant =3∕2
Therefore, pi1−γ⋅Tiγ=pf1−γ⋅Tiγ
‌⇒‌21−3∕2⋅T3∕2‌‌=11−3∕2Tf3∕2‌‌(∵pi=2atm,Ti=T)
⇒‌2−1∕2T3∕2‌‌=1−1∕2Tf3∕2
⇒‌Tf3∕2‌‌=‌

T3∕2

√2

⇒‌Tf‌‌=‌

T

√[3]2