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Question : 26 of 160
Marks:
+1,
-0
Solution:
cot‌h−1(x)=‌‌log(‌),x<−1 or
x>1 and
cosech−1(x)=log(‌+√‌+1),x≠0 ∴coth−1(2)+cosech−1(−2√2) ‌‌‌=‌‌log(‌)+log(‌+√‌+1) ‌‌‌=‌‌log‌3+log(‌+‌) ‌‌‌=log‌√3+log‌=log‌√‌
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