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Question : 14 of 160
Marks:
+1,
-0
Solution:
‌34C5+‌(38−r)C4=‌34C5+‌38C4+‌37C4+ =(‌34C5+‌34C4)+‌36C4+‌35C4+‌36C4+‌37C4+‌38C4 ‌‌[∵‌36C4+‌nCr+1=‌n+1Cr+1] =(‌35C5+‌35C4)+‌36C4+‌37C4+‌38C4 =(‌36C5+‌36C4)+‌37C4+‌38C4 =(‌37C5+‌37C4)+‌38C4=‌38C5+‌38C4=‌39C5
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