TS EAMCET 4-Aug-2021 Shift 1 Question Paper

Bond order (BO)
(Number of electrons in antibonding molecular orbital) - (Number of electrons =‌

‌ in bonding molecular orbital ‌)

2

Here, antibonding molecular orbital electrons denoted by (*)
O2+=σ1s2σ*1s2σ2s2σ*2s2σ2px2(π2py2=π2pz2)
(π*2py1=π*2pz0)
BO=‌

1

2

(10−5)=2.5
O2=σls2σ*1s2σ2s2σ*2s2σ2px2(π2py2=π12pz2)
BO=‌

1

2

(10−6)=2
O2−=σls2σ*1s2σ2s2σ*2s2σ2px2(π2px2=π2py2)
BO=‌

1

2

(10−7)=1.5‌‌(π*2py2=π*2pz1)
O22−=σ1s2σ*1s2σ2s2σ*2s2σ2px2(π2px2=π2py2)
‌‌‌BO=‌

1

2

(π*2py2=π*2pz2)
∴ Correct order of bond order is
O2+>O2>O2−>O22−‌. ‌