TS EAMCET 4-Aug-2021 Shift 1 Question Paper

Section: Mathematics

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Question : 12 of 160

Marks: +1, -0

The equation whose roots are squares of the roots of x4−2x3+6x−21 = 0 is

x4−4x3−18x2−36x+441 = 0
x4+18x3−4x2+36x+441 = 0
x4−2x3+4x2+6x+441 = 0
x4+3x3−5x2+6x+441 = 0

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