TS EAMCET 2017 Code A Solved Paper

The expression to calculate the current is given by,
i=‌‌

e

R′

=‌‌

−∆φ

R′∆t

The value of R′ is equal to R+4R. Therefore,
i=−‌‌

(φ2−φ1)

(R+4R)∆t

=‌‌

(φ2−φ1)

5R∆t

Here, coil has n number of turns.
Therefore
i=−‌‌

n(φ2−φ1)

5R(∆t)

Therefore, the induced current is
i=−‌‌

n(φ2−φ1)

5Rt