TS EAMCET 2017 Code A Solved Paper

Consider the triangle shown below.As per the given condition,
∆=‌‌

1

2

⋅a⋅b‌sin‌c
∆=‌‌

1

2

⋅2⋅1⋅sin‌60∘
∆2=‌‌

3

4

4∆2=3
By using sine rule,
‌‌

sin‌A

a

=‌‌

sin‌B

b

=‌‌

sin‌C

c

‌‌

sin‌A

1

=‌‌

sin‌B

2

=‌‌

sin‌60∘

c

‌‌

sin‌A

sin‌B

=‌‌

1

2

=‌‌

sin‌60∘

c

Consider the last two terms.
‌‌

1

2

=‌‌

‌‌√3∕2

c

c=√3
Using equation (1) and (2)
4∆2+c2=3+3 =6