© examsiri.com
Question : 6 of 160
Marks:
+1,
-0
Solution:
Consider the integration,
I=‌‌.....(1) The above integration can be simplified as,
I=‌‌ l=‌‌| (π−x)dx |
| 4cos2(π−x)+9sin2(π−x) |
=‌‌....(2) Add equation (1) and (2).
2I=‌‌ =‌‌ =‌‌‌‌I=‌‌‌‌‌‌‌Put
tan‌x=tsec
2xdx=dtAt
x=0,t=0x=‌‌,t=∞Then
I=‌‌‌‌‌=‌‌×‌‌[tan−1‌‌]0∞ =‌‌×‌‌×‌‌ =‌‌
© examsiri.com
Go to Question: