TS EAMCET 2017 Code A Solved Paper

Consider the given equation.
2x2−10xy+2λy2+5x−16y−3=0
Compare the given equation with,
ax2+2hxy+by2+2gx+2fy+c=0
On comparing, the value are
a=2,b=2λ,h=−5
g=‌‌

5

2

,f=−8,c=−3
As the given equations represents a pair of straight lines
therefore
|

a	h	g
h	b	f
g	f	c

|=0
|

2	−5	5∕2
−5	2λ	−8
5∕2	−8	−3

|=0
2(−6λ−64)+5(15+20)+‌‌

5

2

(40−5λ)=0
λ=6
The point of intersection is
(‌‌

bg−fh

h2−ab

,‌‌

af−gh

h2−ab

) =(‌‌

30−40

25−24

,‌‌

−16+‌‌ 25 2

25−24

)
=(−10,‌‌

−7

2

)