TS EAMCET 2017 Code A Solved Paper

Consider the given equation of circle,
x2+y2−13=0......(1)
Differentiate the above equation with respect to x
2x+2y‌‌

dy

dx

=0
‌‌

dy

dx

=‌‌

−x

y

The slope of the tangent at (2,3) is
m=‌‌

dy

dx

|(2,3)=‌‌

−2

3

So, the point,
(m,−‌‌

1

m

)=(−‌‌

2

3

,‌‌

3

2

)
Substituting these values in equation (1), we get
‌‌

4

9

+‌‌

9

4

−13=‌‌

16+81−468

36

<0
Therefore, (m,−‌‌

1

m

) is an internal point with respect to the circle