TS EAMCET 2017 Code A Solved Paper

Let S={2k|−9≤k≤10}={−18,−16,...0,2,4,6,...20}
So, total number of possible outcomes are 20 .
From the possible outcomes, only -12,0 and 12 are divisible
by both 4 and 6
So the number of favorable outcomes are 3
The required probability is,
P(E)=‌‌

3

20