TS EAMCET 2017 Code A Solved Paper

Section: Mathematics

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Question : 40 of 160

Marks: +1, -0

If Δ=|

1	5	6
0	1	7
0	0	1

|and Δ′=|

1	0	1
3	0	3
4	6	100

|,then

Δ2−3Δ1=0
(Δ+Δ1)2−3(Δ+Δ1)+2=0
(Δ+Δ1)2−3(Δ+Δ1)+5=0
Δ+3Δ1+1=0

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