TS EAMCET 2017 Code A Solved Paper

The required equation of plane passes through the points (1, -1, 6), ( 0, 0, 7) and perpendicular to the plane x - 2y + z = 6 is calculated as,
|

x−1	y+1	z−6
0−1	0+1	7−6
1	−2	1

|=0
|

x−1	y+1	z−6
−1	1	1
1	−2	1

|=0
(x−1)(1+2)−(y+1)(−1−1)+(z−6)(2−1)=0
3x+2y+z−7=0
The point (1,1,2) satisfy the above equation. Thus, the planepasses through this point.