TS EAMCET 2017 Code A Solved Paper

From the law of conservation of angular momentum
mv1r1=mv2r2
v2=‌‌

v1r1

r2

.....(1)
From the law of conservation of total mechanical energy,
‌‌

−GMm

r1

+‌‌

1

2

mv12=−‌‌

GMm

r2

+‌‌

1

2

mv22........(2)
From equation (1) and (2)
v1=√‌‌

2GMr2

(r1+r2)r1

The angular momentum is calculated as
L=mv1r1
=m(√‌‌

2GMr2

(r1+r2)

)×r1
=m√‌‌

2GMr1r2

r1+r2