TS EAMCET 2016 Code A Solved Paper

Section: Mathematics

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Question : 79 of 160

Marks: +1, -0

The solution of the differential equation 3y′−3y+(x2−y2)

1

2

=0, satisfying the condition y(1)=1 is

3cos−1(
y
x
)=ln|x|
3cos(
y
x
)=ln|x|
3cos−1(
y
x
)=2ln|x|
3sin−1(
y
x
)=ln|x|

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