\int{2x+2}/\sqrt{x^2-4x-5}dx=

Correct Answer is : 2√x2−4x−5+6log|(x+2)+√x2−4x−5|+c

\sqrt{x^2-4x-5}+\text{\log}|x+\sqrt{x^2-4x-5}|+c

\text{\log}|\sqrt{x^2-4x-5}|+\sqrt{x^2-4x-5}+c

\sqrt{x^2-4x-5}+6\text{\log}|(x-2)+\sqrt{x^2-4x-5}|+c

2\sqrt{x^2-4x-5}+6\text{\log}|(x+2)+\sqrt{x^2-4x-5}|+c

TS EAMCET 2016 Code A Solved Paper

Section: Mathematics

Question : 74 of 160

Marks: +1, -0

∫

2x+2

√x2−4x−5

dx=

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