TS EAMCET 2016 Code A Solved Paper

Section: Mathematics

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Question : 53 of 160

Marks: +1, -0

The radical center of the circles x2+y2=1,x2+y2−2x−3=0 and x2+y2−2y−3=0 is

(1,1)
(1,−1)
(−1,1)
(−1,−1)

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