ABCD is a parallelogram and P is a point on the segment \stackrel{-}{AD} dividing it internally in the ratio 3:1.The line \stackrel{-}{BP} meets the diagonal AC in Q.Then AQ : QC =

TS EAMCET 2015 Solved Paper

Section: Mathematics

Question : 76 of 160

Marks: +1, -0

ABCD is a parallelogram and P is a point on the segment

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dividing it internally in the ratio 3:1.The line

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meets the diagonal AC in Q.Then AQ : QC =

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